1. Estabrook's new restroom facilities are known to each be 128 cubic feet in volume. We are tasked with creating a 1:8 scale model of one of the rooms. For the purposes of this analysis, we'll treat the facilities like simple rectangular boxes.
A. What is the volume of the model in dry gallons?
1 dry gallon = 1/8 Winchester bushel
1 Winchester bushel = cylinder 18.5 inches in diameter and 8 inches
deep
B. If the model has a floor area of 36 sq. inches, what is the
height of the real facility?
(include units with answer)
***Please Round to Three Significant Digits for the answers of each Part***
1. Estabrook's new restroom facilities are known to each be 128 cubic feet in volume. We...
1. Estabrook's new restroom facilities are known to each be 128 cubic feet in volume. We are tasked with creating a 1:8 scale model of one of the rooms. For the purposes of this analysis, we'll treat the facilities like simple rectangular boxes. A. What is the volume of the model in dry gallons? 1 dry gallon = 1/8 Winchester bushel 1 Winchester bushel = cylinder 18.5 inches in diameter and 8 inches deep **************DO NOT ROUND************************** B. If the...
Estabrook's new restroom facilities are known to each be 128 cubic feet in volume. We are tasked with creating a 1:8 scale model of one of the rooms. For the purposes of this analysis, we'll treat the facilities like simple rectangular boxes. NOTES IMAGESDISCUSS UNITS STATS HELP Part Description Answer Chk History What is the volume of the model in dry gallons? 1 dry gallon 1/8 Winchester bushel 1 Winchester bushelcylinder 18.5 inches in diameter and 8 inches deep 24.5...
Estabrook's new restroom facilities are known to each be 128 cubic feet in volume. We are tasked with creating a 1:8 scale model of one of the rooms. This model, which is 1/8th the size of the actual restroom facilities, has a volume of 432 cubic inches or 0.25 cubic feet. For the purposes of this analysis, we'll treat the facilities like simple rectangular boxes. Hints given: Hint #1:Volume = floor area x height. Hint #2: First find the height...