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0.5 cm 600 ML 1. Internal radius of rubber tube, r: 2. Length of segment of rubber tube filled with air, e: 3. Volume of tube
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Answer #1

1 atm = 760 torr = 10332.276 mm H2O

V(ml) P (mm H2O) 1/P (1/mm H2O) PV (mm H2O *mL)
30 10332.276 0.00009678 309968.28
25 10343.276 0.00009668 258581.9
20 10351.776 0.00009660 207035.52
15 10357.276 0.00009655 155359.14
10 10366.776 0.00009646 103667.76
5 10372.776 0.00009641 51863.88

PV from graph = 6.67x107 mmH2O x mL

V vs 1/P - V(ml) = 6.67E+07*x + -6426 V (ml) 0.00009645 0.00009650 0.00009655 0.00009660 0.00009665 0.00009670 0.00009675 1/P

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