Solution:
Let random variable Z is the linear combination of two independent random variables X and Y.
then,
Z=aX+bY
Mean(μz)=aμx+μy
Variance(Vz)=a2σ2x+b2σ2y
X | P(x) | X*P(x) | X2*P(x) | Y | P(y) | Y*P(Y) | Y2*P(Y) |
0 | 0.12 | 0 |
0 |
0 | 0.18 | 0.0 | 0 |
1 | 0.29 | 0.29 | 0.29 | 1 | 0.38 | 0.38 | 0.38 |
2 | 0.42 | 0.84 | 1.68 | 2 | 0.34 | 0.68 | 1.36 |
3 | 0.17 | 0.51 | 1.53 | 3 | 0.10 | 0.30 | 0.9 |
Total | 1.0 | 1.64 | 3.50 | Total | 1.0 | 1.36 | 2.64 |
Number of Food Number of Service Probabilit 0.12 0.29 0.42 0.17 laints 0.18 0.38 0.34 0.10...
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