Question

6.20 Mean OC in young women. Refer to the previous exercise. A biomarker for bone formation measured in the same study was osteocalcin (OC), measured in the blood. For the 31 subjects irn the study, the mean was 334 nanograms per milliter (ng/ml). Assume that the standard deviation is known to be 19.6 ng/ml. Report the 95% confidence interval.

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Answer #1

solution:-

given that n = 31 , mean = 33.4 , standard deviation = 19.6

95% confidence for z is 1.96

confidence interval formula

=> x +/- z * s/sqrt(n)

=> 33.4 +/- 1.96 * 19.6/sqrt(31)

=> 33.4 +/- 6.8997

=> (26.50 , 40.30)

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