Question

44 points 0sU Phys1 3.3 P.040 My Notes Ask Yor A commuter backs her car out of her garage with a constant acceleration of 1.50 m/s a) How long in seconds does it take her to reach speed of 2.00 m/s? (b) It she then brakes to a scop in 0.8 s, what is her (constant) deceleration in m/s? m/s? .4 points 05U Pry1 33.7021 My Notot A particlais traveling along thฉ x axis with constant acceleration and a record of its position as function of ชme is shown in the figure for a six second tima interval. x (m) 200 150 100 50 t (s) A tangent line has been drawn att-1.00 s and this line also passes through the point (6.00 s, 104.0 m. A second tangent line has been drawn at t5.00 s and this line also passes through the point (2.00 s, 8.0 m Time ts)1.00 2.00 3.00 4.00S.C0.00 Positon xm) 12.0 24.0 44.0 72.0 10. 152.0 204.0 (a) Find the average velocity over the time interval t = (0 vrt (0 . 2.00%) . 2.00) s and the instantaneous velocity at the time c = 1.00 s. mys r(t = 1.00 s- (b) Find the average velocty over the trme interval t-(4.00 水" (4.00 → 6.00) s- > 6.00) s and the nstantaneous velocity at the time t-5.00 s. vi-5.00 3) mU's (c) Find the the acceleration of the object as it travels alorg the x axis. m/s2

Answer 1

4) a) using the equation

v = u + at

2 =0 + 1.5*t

t = 1.33 s

b) v= u + at

0 = 1.33 + a*0.8

a = -1.67 m/s2

so deacceleration = -1.67 m/s2