Question

What is the magnitude of the force on a proton at the midpoint? Express your answer with the appropriate units. Review Two 10-cm-diameter charged rings face each other, 20 cm apart. The left ring is charged to 30 nC and the right ring is charged to t30 nC You may want to review (Pages 641 643) 3.9 10 Submit Previous Answers Request Answer Incorrect; Try Again: 2 attempts remaining Part D What is the direction of the force F on a proton at the midpoint? to the left ring to the right ring

Answer 1

Force on a proton at point p is given by F_Net = F_1 + F_2 {because of symmetry of location of p Q_1 = Q_2 = theta} rightwardsdoublearrow F_Net = 2F_1 rightwardsdoublearrow F_Net = 2 [K theta z g/(z^2 + R^2)^3/2] rightwardsdoublearrow F_Net = 2 times 9 times 10^9 times 30 times 10^-9 times 0.1 times 1.6 times 10^-19/(0.1 + 0.05^2)^3/2 F_Net = 6.182 times 10^-15 N direction to the left ring.