Question

How many grams of N 2 are produced when 125 g of NH 3 reacts as shown in the following balanced equation? 5N2 6H20 4NH3+ 6NO
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Answer #1

Let x be the amount of N2 released by 125 g of NH3

4*17 g of NH3 gives----------> 5*28 g of N2

125 g of NH3 gives------------> x g of N2

Cross multiply

4*17*x=125*5*28

X= 257 g

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