Question

A thin metallic spherical shell of radius 0.247 m has a total charge of 9.03 Times 10^-6 C placed on it. At the center of the shell is placed a point charge of 4.15 Times 10^-6. what is the electric field at a distance of 0.855 m from the center of the spherical shell? inward outward

Answer 1

Given,

R = 0.247 m ; Q = 9.03 x 10^-6 C ; q = 4.15 x 10^-6 C ;

We need to find the E field distant r = 0.855 m from the center of the shell.

We know from Gauss law that,

E x A = Q(total) / $\epsilon$o

E = Q(total) / A $\epsilon$o

E = 1/4 pi $\epsilon$o x Q(total)/r²

E = 9 x 10⁹ x (9.03 + 4.15) x 10^-6 / (0.855)² = 1.62 x 10⁵ N/C

Hence, E = 1.62 x 10⁵ N/C

Direction : Outwards