This is a fairly straightforward two-step problem. Our first step is to convert the given grams of reactant (KNO3) to moles:
Next, we use the balanced reaction equation (given in the problem) to see that for every 4 moles of KNO3 that react, we get 5 moles of O2 (Oxygen). Usin gthis information, we can determine how many moles of Oxygen we will get when our given 0.579 moles of KNO3 react:
This is our final answer which corresponds with choice "A"
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9) How many moles of oxygen are formed when 58.6 g of KNO3 decomposes according to...
9) H ow many moles of oxygen are formed when 58.6 g of KNO3 decomposes according to thefollowing reaction? The molar mass of KNO3 is 101.11 g/mol.4 KNO3(s) ? 2 K2O(s) + 2 N2(g) + 5 O2(g)
9) H ow many moles of oxygen are formed when 58.6 g of KNO3 decomposes according to the following reaction? The molar mass of KNO3 is 101.11 g/mol. 4 KNO3(s) ? 2 K2O(s) + 2 N2(g) + 5 O2(g)
Module 9 5. How many moles of oxygen are formed when 58.6 g of KNO3 decomposes according to the following reaction? The molar mass of KNO3 is 101.11 g/mol. Half Credit for the right answer and half credit for showing work 4 KNO3(s) → 2 K20(s) + 2 N2(g) + 5 O2(g) A) 0.290 mol O2 B) 0.580 mol O2 C) 18.5 mol O2 D) 0.724 mol O2 E) 1.73 mol O2
DJ 01.03% E) 20.02% 3) How many moles of oxygen are formed when 58.6 g of KNO3 decomposes according to the following reaction? The molar mass of KNO3 is 101.11 g/mol. 4 KNO3(s) - 2 K2O(s) + 2 N2(g) +502(8) A) 0.290 mol O2
Question 5 (2 points) How many moles of oxygen are formed when 58.6 g of KNO3 decomposes according to the following reaction? The molar mass of KNO3 is 101.11 g/mol. 4 KNO3(s) 2 K20(s)2 N2(g) + 5 O2(g) 0.290 mol 02 0.580 mol02 18.5 mol 02 0.724 mol 02 1.73 mol 02
4KNO3(s)----->2K2O(s)+2N2(g)+5O2(g) How many moles of oxygen are formed when 58.6 g of KNO3 decomposes according to the following reaction? The molar mass of KNO3 is 101.11 g/mol.
How many moles of nitrogen are formed when 58.6 g of KNO, decomposes according to the following reaction? The molar mass of KNO, is 101.11 g/mol. 4 KNO3(s) + 2 K 0(s) +2 N2(g) + 5O2(g) 18.5 mol N2 1.73 mol N2 0.290 mol N2 0.580 mol Ng 0.724 mol N2 Submit Request Answer
How many grams of nitrogen gas are formed when 10.0 g of KNO3 decomposes according to the following reaction? The molar mass of KNO3 is 101.11 g/mol 4 KNO3(s) - 2 K2O(s) + 2 N2(8) + 5 O2(8) O 0.698 O 0.362 g 2.778 1.388
How many moles of nitrogen are formed when 50.7 g of KNO3 decomposes according to the following reaction? 4 KNO3(s) → 2 K2O(s) + 2 N2(g) + 5 O2(g)
27. How many moles of nitrogen are formed when 25.0 g of KNO3 decomposes according to the following reaction? The molar mass of KNO3 is 101.1 g/mol. How many moles of oxygen are formed? Potassium? 4KNO3(s) → 2K2O(s) + 2N2(g) + 5O2(g) Also, if someone could explain how to obtain the conversion factor, that'd be great. I understand the process of solving a problem like this goes: mass → molar mass → stoich → molar mass → mass, correct? I'd...