Question

In the winter sport of curling, players give a 20kg stone a push across a sheet of ice. A curler accelerates a stone to a speed of 3.1m/s over a time 2.2s

a) How much force does the curler exert on the stone?

b) What average power does the curler use to bring the stone up to speed?

Answer 1

Answer 2

To find force, you need to know acceleration. To find that, you can use the final velocity equation:

Vfinal = Vinitial + a*t
3.1 = 0 + 2.2a
a = 1.409

F = ma = 1.409*20 = 28.18N

Average power is the value of the total work done divided by the time it took to do the work.

Work = Force*Distance, so we need distance. We can use the displacement equation.

x = Vinitial*t + (1/2) at^2
x = 0 + (1/2) (1.409)(2.2)^2
x = 3.40978 m

Work = F*d = 28.18*3.40978 = 96.0876 J

Average Power = W / t = 96.0876 / 2.2 = 43.676 watts

Answer 3

a)force that the curler exert on the stone =ma

a=v/t =3.1/2.2 =1.409 m/sec^2

F=Ma= 20*1.409= 28.18 N (ans)

b)average power =Fv =28.18*3.1 =87.358 W (ans)