Problem - 3
Length of the organ pipe, L = 26 cm
=
0.26 m
Velocity of sound, V = 343 m/s
(a)
Frequency, f = n V / 2 L , for n = 1, 2, 3 ,
...( pipe , two open ends )
where
n = harmonic number
Fundamental frequency, f = ( 1) * ( 343 ) / 2 *(
0.26 ) = 659.6 Hz
Frequency of first overtone = 2f =
1319.23Hz
Frequency of second overtone = 3f =
1978.8Hz
Frequency of third overtone = 4f = 2638.4
Hz
(b)
Frequency, f = n V / 4 L , for n = 1, 3, 5 , ...
(pipe, one open end )
where
n = harmonic number
Fundamental frequency, f = ( 1) * ( 343 ) / 4 *(
0.26 ) = 329.8 Hz
Frequency of first overtone = 3f = 989.4
Hz
Frequency of second overtone = 5f = 1649
Hz
Frequency of third overtone = 7f = 2308.6
Hz
3. What will be the fundamental frequency and first overtone for a 26-сm long organ pipe...
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