In the synthesis of ammonia, what is the percentage yield of ammonia when 100.kg of hydrogen...
In the synthesis of ammonia, what is the percentage yield of ammonia when 100.kg of hydrogen reacts with 800.0kg of nitrogen to produce 400.0kg of ammonia?
Homework Answers
6kg of hydrogen requires 28 kg of nitrogen to produce 34 kg of ammonia.
thus 100 kg of hydrogen requires (100/6)*28 kg =466.67 kg of nitrogen to produce (100/6)*34 kg=566.67 kg of ammonia
But 400 kg of ammonia was obtained.Thus percentage yield is (400/566.67)*100 %=82.35 %
Just put values in this example
Calculating Percentage Yield
112g of nitrogen gas reacts with hydrogen gas to produce 40.8g of ammonia gas according to the equation given below:
N2(g) + 3H2(g)
2NH3(g)
Calculate the percentage yield of ammonia.
- Actual yield of ammonia (NH3) = 40.8g
- Theoretical yield of ammonia (NH3) is calculated
using the equation:
moles = mass
Add Answer to:
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