magnitude of vector = 33.1 ft
X component of vector=12.9 ft
let magnitude of Y component be y
33.12=12.92+y2
y=30.48 ft
given vector has downward y component
therefore, y component of vector = -30.48 ft
angle of vector measured counterclockwise from X axis = 360-tan-1(30.48/12.9)=292.94o
A bird uses a coordinate system of X to the right and Y upwards. The bird...
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