QUESTION 3 A solution is prepared by mixing 30.0 mL of 0.60 M Ba(NO3)2 and 30.0...
A student adds 0.0035 mol of NaF to 1.00 L of 0.02 M barium nitrate, Ba(NO3)2. Which of the following statements is correct? Ksp = 1.5 × 10–6 for BaF2. Assume there is no volume change upon addition of NaF. One must know Ksp for barium nitrate to make a determination Barium fluoride precipitates until the solution is saturated. The solution is unsaturated and no precipitate forms. The solubility of barium fluoride is increased upon the addition of fluoride ions....
ID: A A solution has 2.00 x 10-3 M Ba(NOs)2 and 0.0500 M KF. Given that 1.5 x 106, will a preicipitate of BaF form in this condition. (3 pts.) the Ksp of barium fluoride is Ba(NO3)2 + 2KF BaF2 + 2KNO ID: A A solution has 2.00 x 10-3 M Ba(NOs)2 and 0.0500 M KF. Given that 1.5 x 106, will a preicipitate of BaF form in this condition. (3 pts.) the Ksp of barium fluoride is Ba(NO3)2 +...
4- (a) Calculate the concentration of Cd2+ ion in a solution prepared by mixing 2.0 mL of 1 M CA(NO3)2 solution with 1.0 L of 4.0 M NH3 solution. [Assume that the volume does not change after the addition of 2.0 ml of 1 M Cd(NO3)2] (b) Will you be able to see Ca(OH)2(6) precipitate in the solution? (Kr for Ca(NH3)42+ = 1.0 x 107, Kb for NH3 = 1.8 x 10-5; Ksp for Ca(OH)2 = 5.9 x 10-15 Cd2+...
You prepare a solution by mixing 400.0 mL of 1 x 10-4 M Mg(NO3)2 and 500.0 mL of 1.00 x 10-4 M NaF. What is the observed outcome? For MgF2, Ksp = 6.4 x 10-9. A. A precipitate forms because Qsp > Ksp. B. No precipitate forms because Qsp > Ksp. C. No precipitate forms because Qsp = Ksp. D. No precipitate forms because Qsp < Ksp. E. A precipitate forms because Qsp < Ksp.
A solution of 0.1 L of 0.3 M Ca(NO3)2 is mixed with 0.2 L of 0.06 M NaF. Calculate the reaction quotient Qsp. Does calcium fluoride precipitate? (Ksp (CaF2) = 3.2×10–11). (A) Qsp = 1.6×10–4; no precipitate. (B) Qsp = 1.6×10–4; a precipitate will form. (C) Qsp = 3.2×10–11; no precipitate. (D) Qsp = 3.2×10–11; a precipitate will form. (E) Qsp = 3.2×10–7; no precipitate.
Calcium fluoride, CaF2, is an insoluble salt (Ksp = 1.46 x 10-10) that can be formed by precipitation by mixing solutions of calcium nitrate and sodium fluoride. Suppose 200.0 mL of a 0.600 M Ca(NO3)2(aq) solution are mixed with 400.0 mL of a 0.0600 M NaF(aq) solution. Will a precipitate form? How much calcium fluoride could form?
A solution is prepared by mixing 150mL of 1.00 x 10-2 M Mg(NO3)2 and 250 mL of 1.00 x 10-1 M NaF. How much solid MgF2 (in milligrams) if any will remain? (Ksp of MgF2 is 6.4 x 10-9 )
pt Solid Na SO, is added slowly to a solution that is 0.76M in Pb(NO3), and 0.45M in Ba (NO3),. In what order will solid PbSO4 and BaSO4 form? Calculate the percentage of Ba2+ that precipitates just before PbSo, begins to precipitate. Assume that Ksp (PbSO4) = 1.8 x 10-8 and Kg (BaSO4) = 1.1 x 10-20 will precipitate first. pe Percentage =
if 125 mL of a solution containing 0.0400 M of Pb(NO3)2 (aq) is mixed with 75.0 mL of a solution containing 0.0200 of NaCl(aq), will there be a precipitate? PbCl3 has a Ksp value of 1.6 x 10^-5. Assume volumes are additive when mixed
A solution is prepared by mixing 47.00 mL of 0.024 M AgNO3 with 11.00 mL of 1.0×10-3M Na2CO3. Assume that volumes are additive. Calculate [Ag+], [CO32–], [Na+], and [NO3–] after equilibrium is established. [Ag+]= [CO32+]= [Na+]= [NO3-]=