Hope this helps!!
Thank you
sin x aln3' nena) xln tan1 (x - Vx2 +1) Q1/Find the Derivatives: 1) y 2)...
2. Find the intervals on which the following function is continuous. tan r B( ) = V4-12 3. Find the derivatives of the following functions (a) f(z)= /5x +1 (b) gla) = (2r -3)(a2 +2) (c) y = In (x + Vx2 - 1) 4. Find the intervals on which the following function is decreasing. f(z) = 36x +3r2 - 2r 5. Evaluate the following integrals. r dr (a) sec2 tan (b) dar 3 (c) da 5x+1 1. Sketch the...
10) Integrate f(x, y) = sin (Vx2 + y2) over the region 0 < x2 + y2 = 16
Question 2 (20 points): Consider the functions f(x, y)-xe y sin y and g(x, y)-ys 1. Show f is differentiable in its domain 2. Compute the partial derivatives of g at (0,0) 3. Show that g is not differentiable at (0,0) 4. You are told that there is a function F : R2 → R with partial derivatives F(x,y) = x2 +4y and Fy(x, y 3x - y. Should you believe it? Explain why. (Hint: use Clairaut's theorem) Question 2...
Q1. Find affox and af/ày. f(x,y) = x2 + 5xy + sin x + 7e* (4 marks)
Find all the first and second order. partial derivatives of f(x, y) = 8 sin(2x + y) - 2 cos(x - y). A. SI = fr = B. = fy = c. = f-z = D. = fyy = E. By = fyz = F. = Sxy=
QUESTION 8 Evaluate the integral. dx Vx2 - 10x + 21 x-10) sin + C 2 X-5 tan +C 2 2 sin -1 X-5 2 +C x + 5 sin! + 2
3. Find the derivatives and 24, where z = sin xy, 1 = st and y = (s + 1) 10
a. Use the Chain Rule to find the indicated partial derivatives. z = x4 + x2y, x = s + 2t − u, y = stu2; ∂z ∂s ∂z ∂t ∂z ∂u when s = 1, t = 2, u = 3 b. Use the Chain Rule to find the indicated partial derivatives. w = xy + yz + zx, x = r cos(θ), y = r sin(θ), z = rθ; ∂w ∂r ∂w ∂θ when r = 8, θ = pi/2 c. Use the...
1. Find the derivatives of the functions sina (a) y=V7+ xsecx (b) y cot cot (c) y = (rtant) 2. Find y' if (i) y = CSC X (ii) y = secx (iii) y = sec xtan (iv) y = sin x tane
Evaluate the integral. dx Vx2 - 4x - 12 of tani *(x-2) + c sin +C X sin +C 4 sin +C Could you help me in this QS, with steps, and make sure that the final solution from the options :)