Question

2 of 3 229 (h) Note: Link 4 and link 6 can slide only 45 typ Symmeical meche Consider that front end loader (Figure "r and ") is stationary (not moving) during working Piston () Piston 2 Hydraulic Cylinder U) Hydraulic Cylinder Bucket

calculate the mobility of linkages and define mechanism of each case clearly & define number of link, number of joint full (lower pair & higher pair )

Answer 1

(h)

No of link n=9

No of lower binary pair =6

No of lower tertiary pair =3

Since one tertiary pair is equi

No of link n=9

No of lower binary pair =6

No of lower tertiary pair =3

Since one tertiary pair is equivalent

valent to two binary pair Then total no of lower pair j=6+3*2 =12

Since there is no higher pair h=0

We know mobility

m= 3(n-1)-2j-h

=3(9-1)-2*1

No of lower binary pair =6

No of lower tertiary pair =3

Since one tertiary pair is equivalent to two binary pair

Then total no of lower pair j= 6+3*2 =12

Since there is no higher pair h=0

We know mobility

m= 3(n-1)-2j-h

=3(9-1)-2*12-0

m=0

2-0

m=0

(I)

No of link n =

No of lower binary pair =9

No of lower tertiary pair =1

Since one tertiary pair is equivalent to two binary pair

Then total no of lower pair j= 9+1*2 =11

Since there is no higher h=0

We know mobility

m=3(n-1)-2j-h

=3(9-1)-2*11-0

m=2

(J)

No of link n=11

No of lower binary pair =12

No of lower tertiary pair =1

Since one tertiary pair is equivalent to two binary pair

Then total no of lower pair j= 12+1*2 =14

Since there is no higher h=0

We know mibmobil

m=3(n-1)-2j-h

=3*(11-1)-2*14-0

m=2