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D Question 3 60 mi 24 mm 15 m 1s0 me Pl 32 16 mm 30 mm P2 applied to the bar shown with P1 - 750 N, P2 - 500 N and P3 - 10N.
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Answer #1

Draw the free body diagram of the bar in x-y plane:

750N -180 mm M, Bending moment about z-axis from the above figure is M 750Nx180mm 135000 N mm -135N-m Draw the free body diag

Area of the bar is, A=bd 60 x32 1920mm Calculate the moment of inertia about z-axis. bd3 12 60x323 12 4 -163.84x103 mm Calcul

Calculate the normal stress at pointt a using the following equation

P Mry Mr + I. 135 103N.mm* 16mm 163.84 10-37mm4 A IT 10 103N 0 1920mm2 5.20813.183 18.391 N/mm2

a=18.391 MPa

Draw the free body diagram of the bar in y-z plane:

32 mm 15 mm moment about the neutral axis is Q-Az First 30 (32x30) - 14.4x10 mm Write the equation to calculate shearing stre

Ta = 0.39 MPa

Calcul ate normal shear stress at point b by using the followir equation A,y Mz =_+ 10x10 N 135x103 N mm x16 mm + 4 mm 163.84

Cb=21.3 MPa

Tb0.292 MPa |

Calculate the normal shear stress at point c using the equation Mz + I. P M,y =_+ A 10x10N 135x10 N mm x16mm 163.84x10 mm +

24.12 MPa o

There is no thickness.Therefore,the shear stress will become zero

\tau _c=0

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