Dimensional Analysis min = A (Kg^2) + Be^(2min/C) + D (0.815min/K) - E60min^0.5 How do you...
Dimensional Analysis
min = A (Kg^2) + Be^(2min/C) + D (0.815min/K) - E60min^0.5
How do you determine the unknown constants for C, D, and E?
I am completely lost..
Homework Answers
if A=B+C+D
Then dimension of A=dimension of B=dimension of C.![0.5 [ ]→ Dimension Notation [ ] Tis time his mass I S](http://img.homeworklib.com/questions/5589e070-633f-11ea-8267-c33c08e8d6be.png?x-oss-process=image/resize,w_560)
![LDCo.Li5 minl k [A): [ kg-2min] [m2t] or Dimension of A is dumensionless e. TheDimension o C-IT Cu IminCD Co815 min/k) Dimensiono D s Ce](http://img.homeworklib.com/questions/560c26c0-633f-11ea-a849-757f9edb498b.png?x-oss-process=image/resize,w_560)
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Dimensional Analysis
min = A (Kg^2) + Be^(2min/C) + D (0.815min/K) - E60min^0.5
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Your patient is to receive dopamine 5 mcg/kg/min. He weighs 176 lb. You have dopamine 400 mg in 500 mL D5W. You will infuse this at which rate? A. 20 ml/hr B. 30 mL/hr 0.35 mL/hr D. 50 ml/hr When assessing for diovascular effects of an
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size?
I want to create an array of unknown dimensional size based on a
number I recieve. To elaborate, let's say n = 2, it will output a
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array {true, true, true, true}. Whatever the n value is, the return
value will be an array of n + 1 dimensional size. How would...
Not sure if i balanced the equation out. I am completely lost
on how to do A and B. thanks for the help in advance
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