FIrst of all we need to need to know the volume of mud that descends:
As mountain side measuring 1.1 km horizontally, 0.73km up along the incline, and 2.3 m deep:
1100 X 730 X 2.3 = 1846900m^3 of mud.
Region of the valley = 1200 X 1200 = 1440000m^2
Depth of the mud in the region of valley = 1846900/1440000 = 1.28 m
Now we can calculate the volume of mud covering the region being referred to(3.2 m2)
= 1.28 x 3.2 = 4.096 m^3
Now mass = density x volume = 4.096 x 1900 = 7782.4 kg
Chapter 01, Problem 025 During heavy rain, a section of-mountainside measuring 1.1 km horizontally perpendicular to...
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Calculus-based Physics: For the following question, you will work on mass and time as discussed in this chapter, and you will do Part 1) (a) Assuming that each cubic centimeter of water has a mass of exactly 1 g, find the mass of 4.38 cubic meter of water. (b) Suppose that it takes 10.4 hours to drain a container of 24.0 m3 of water. What is the "mass flow rate," of water from the container?\ Part 2) During heavy rain,...