Question

(1) After landing on an unfamiliar planet, a space explorer constructs a simple pendulum from a massless rod of length 50.0 cm. The bob mass is 0.20 Kg. (Reminder: a bob is the mass on the end of the pendulum.) The bob is pulled from the vertical by an angle of 5° and released. The pendulum executes 100 complete cycles in 163 s. (a) What is the gravitational strength g at that location on the planet? (10 points) (b) What is the maximum speed of the bob and how much time does it take for the bob to reach its maximum speed ? [hint: remember that the unit for the absolute value of an angle is radians.] (15 points) (c) The bob mass is now doubled to 0.40 Kg and is released from an angle of 10°. Now what is the maximum speed and how long does it take the bob to reach this speed? (6 points)163 5 O a) 100 o.50m di dt Imax (s, are length) convert to The maximum s peed is thus 2 TT 二10.168 m/s 163 The time it takas to rea dh this speed is***So my question is why did my professor divide by 4 at the end of part b? Please explain and show work if possible.

0 0
Add a comment Improve this question Transcribed image text
Answer #1

At T/4 the velocity is maximum because the bob is at the lowest position of the pendulum when string makes 0 degree with vertical. At lowest position the gravitational potential energy is minimal and kinetic energy is maximum.

bob endulum. 3寸 st onal D maximm 4-

Add a comment
Know the answer?
Add Answer to:
***So my question is why did my professor divide by 4 at the end of part...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
  • On the planet Newtonia, a simple pendulum having a bob with a mass of 1.31 kg...

    On the planet Newtonia, a simple pendulum having a bob with a mass of 1.31 kg and a length of 188.2 cm takes 1.58 s , when released from rest, to swing through an angle of 11.5 ∘, where it again has zero speed. The circumference of Newtonia is measured to be 5.14×104 km . What is the mass of the planet Newtonia? (in kg)

  • On the planet Newtonia, a simple pendulum having a bob with a mass of 1.26 kg...

    On the planet Newtonia, a simple pendulum having a bob with a mass of 1.26 kg and a length of 185.4 cm takes 1.59 s , when released from rest, to swing through an angle of 12.4 ∘, where it again has zero speed. The circumference of Newtonia is measured to be 5.16×104 km . What is the mass of the planet Newtonia in kg?

  • On the planet Newtonia, a simple pendulum having a bob with mass 1.30 kg and a...

    On the planet Newtonia, a simple pendulum having a bob with mass 1.30 kg and a length of 155.0 cm takes 1.42 s , when released from rest, to swing through an angle of 12.5 ∘ , where it again has zero speed. The circumference of Newtonia is measured to be 51400 km . What is the mass of the planet Newtonia?

  • On the planet Newtonia, a simple pendulum having a bob with a mass of 1.34 kg...

    On the planet Newtonia, a simple pendulum having a bob with a mass of 1.34 kg and a length of 186.3 cm takes 1.42 s , when released from rest, to swing through an angle of 11.8 ∘, where it again has zero speed. The circumference of Newtonia is measured to be 5.14×104 km . What is the mass of the planet Newtonia?

  • The length of a simple pendulum is 0.66 m, the pendulum bob has a mass of...

    The length of a simple pendulum is 0.66 m, the pendulum bob has a mass of 305 grams, and it is released at an angle of 11° to the vertical. (a) With what frequency does it vibrate? Assume SHM. Hz (b) What is the pendulum bob's speed when it passes through the lowest point of the swing? m/s (c) What is the total energy stored in this oscillation, assuming no losses? J My Notes Ask Your Teacher 8. -13 points...

  • A simple pendulum has a mass of 0.650 kg and a length of 5.00 m. It...

    A simple pendulum has a mass of 0.650 kg and a length of 5.00 m. It is displaced through an angle of 9.0° and then released. Using the analysis model of a particle in simple harmonic motion, calculate the following. (Give your answer to the thousandths place.) (a) What is the maximum speed of the bob? m/s (b) What is the maximum angular acceleration of the bob? ? rad/s2 (c) What is the maximum restoring force of the bob? ?...

  • P4. A clock keeps time using the periodic motion of a simple pendulum. The pendulum consists...

    P4. A clock keeps time using the periodic motion of a simple pendulum. The pendulum consists of a string of length L and a bob of mass m-5.00 kg attached to the end of the string. The pendulum has a period T-1.00 s. The initial angle (0) at 0 is equal to 0.175 rad. The bob is released from rest (i.e. -0) at -0. The angle between the string and the vertical is given by the equation: e-a cos (or...

  • A simple pendulum with mass m = 2.3 kg and length L = 2.62 m hangs...

    A simple pendulum with mass m = 2.3 kg and length L = 2.62 m hangs from the ceiling. It is pulled back to an small angle of θ = 9.2° from the vertical and released at t = 0. 1) What is the period of oscillation? 2) What is the magnitude of the force on the pendulum bob perpendicular to the string at t=0? 3) What is the maximum speed of the pendulum? 4) What is the angular displacement...

  • A simple pendulum with mass m = 2.1 kg and length L = 2.79 m hangs...

    A simple pendulum with mass m = 2.1 kg and length L = 2.79 m hangs from the ceiling. It is pulled back to a small angle of θ = 11.5° from the vertical and released at t = 0. 1) What is the period of oscillation? 2) What is the magnitude of the force on the pendulum bob perpendicular to the string at t=0? 3) What is the maximum speed of the pendulum? 4) What is the angular displacement...

  • Please answer with the correct amount of significant figures. Thank you!! A simple pendulum has a...

    Please answer with the correct amount of significant figures. Thank you!! A simple pendulum has a mass of 0.650 kg and a length of 7.00 m. It is displaced through an angle of 8.0° and then released. Using the analysis model of a particle in simple harmonic motion, calculate the following. (Give your answer to the thousandths place.) (a) What is the maximum speed of the bob? m/s 4.0 (b) What is the maximum angular acceleration of the bob? |...

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT