The height of a cannon off the ground is 3m, the angle is 0 degrees (horizontal),...
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The
height of a cannon off the ground is 3m, the angle is 0 degrees
(horizontal),...
Also... If I have a launch height of 3m and a distance of 79.45.. angle is...
Also... If I have a launch
height of 3m and a distance of 79.45.. angle is 30 degrees, and
velocity is 30 m/s... What would be the range of that projectile?
Answers to both would help tremendously.
Predict and Test Vertical Height Calculate the initial speed needed to shoot a target directly above the cannon (90 degrees) at a height of 25.0 m (show work). Use the tape measure to place a target 25.0 m above the cannon and test...
A. A cannon is fired over level ground at an angle of 30 degrees to the...
A. A cannon is fired over level ground at an angle of 30 degrees to the horizontal. The initial velocity of the cannonball is 500 m/s but because the cannon is fired at an angle, the vertical component of the velocity is 250 m/s and the horizontal component is 433 m/s. How long is the cannonball in the air? (Use g = -10 m/s2) B. A cannon is fired over level ground at an angle of 30 degrees to the...
A water balloon is tossed at an angle of phi = 47 degrees above the horizontal,...
A water balloon is tossed at an angle of phi = 47 degrees above the horizontal, from a height of 1.50 m above the ground to a target located at delta x = 16 m away. The target is located on a platform h = 3.6 m above the ground. What must the initial speed of the water balloon be to hit the target?
Consider a projectile launched at a height h feet above the ground and at an angle θ with the hor...
Consider a projectile launched at a height h feet above the ground and at an angle θ with the horizontal. If the initial velocity is v0 feet per second, the path of the projectile is modeled by the parametric equations x = t(v0 cos(θ)) and y = h + (v0 sin(θ))t − 16t2. The center field fence in a ballpark is 10 feet high and 400 feet from home plate. The ball is hit h = 2 feet above the...
A cannon fires a cannonball at an angle of 30 degrees about horizontal. The initial velocity...
A cannon fires a cannonball at an angle of 30 degrees about horizontal. The initial velocity of the cannonball is 40 m/s. A) How long will it take the cannonball to reach maximum height B) What is the maximum height the cannonball will reach C) What distance in x will the cannonball travel before hitting the ground?
A cannon is fired over level ground at an angle of 30 degrees to the horizontal....
A cannon is fired over level ground at an angle of 30 degrees to the horizontal. the initial velocity of the cannonball is 400 m/s but because the cannon is fired at an angle, the vertical component of the velocity is 200 m/s and the horizontal component is 346 m/s a. How long is the cannonball in the air (use 10 m/s^2 and the fact thatthe total time of flight is twice the time required to reach the high point.
A cannon shoots a cannonball from the ground level (ignore the height of the cannon) towards a cliff of height h = 170 m
A cannon shoots a cannonball from the ground level (ignore the height of the cannon) towards a cliff of height h = 170 m. The cannonball is launched with an initial velocity of 110 m/s at an angle of 64° above the horizontal. Neglect air resistance. Assume the cannonball hits the cliff as it descends (on its way down) exactly at the edge, as shown. a. Determine the maximum height above the ground reached by the cannonball.b. What speed will the...
A cannon launched a cannon ball at 30 degrees off the ground, at 40 m/s. What...
A cannon launched a cannon ball at 30 degrees off the ground, at 40 m/s. What is the speed of the cannon ball 1) at 3.2 seconds, and 2) when it hits the ground? (Find vertical and horizontal velocity components first).
A large cannon is fired from ground level over level ground at an angle of 55...
A large cannon is fired from ground level over level ground at an angle of 55 above the horizontal. This initial speed is 384 m/s. Neglecting air resistance, how far will the projectile travel in the horizontal direction before striking the ground?
A projectile is launched from ground level with an initial speed of 40m/s at an angle...
A projectile is launched from ground level with an initial speed of 40m/s at an angle of 0.6 radians** above the horizontal. It strikes a target 2.2 seconds later. What is the vertical distance from where the projectile was launched to where it hit the target?
Also... If I have a launch
height of 3m and a distance of 79.45.. angle is 30 degrees, and
velocity is 30 m/s... What would be the range of that projectile?
Answers to both would help tremendously.
Predict and Test Vertical Height Calculate the initial speed needed to shoot a target directly above the cannon (90 degrees) at a height of 25.0 m (show work). Use the tape measure to place a target 25.0 m above the cannon and test...
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