Question

A toy is thrown vertically upward with a speed of 12m/s from the edge of a cliff 75m high. How much later does it reach the bottom of the cliff? Whats its speed just before hitting the ground? What total distance did it travel?

Answer 1

$\\ALONG\;VERTICAL\;\\\\ initial\;velocity\;v_{oy}=1.8\;m/s\\\\ acceleration\;a_y=-g=-9.8\;m/s^2\\\\ initial\;position\;y_o=26\\\\ (i)\\\\ final\;position\;y=0\\\\ from\;equation\;of\;motion\\\\ y-y_{o}=v_{oy}t&plus;\frac{1}{2}a_{y}t^2\\\\ 0-26=(1.8)(t)-\frac{1}{2}(9.8)(t^2)\\\\ t=2.5\;s\;<<<------answer\\\\$