(1 point) Set up a double integral for calculating the flux of F -4xi + yj + zk through the part of the surface z =-2x-4y + 4 above the triangle in the xy-plane with vertices (0,0), (0,4), and (2,0), oriented upward. Instructions: Please enter the integrand in the first answer box. Depending on the order of integration you choose, enter dx and dy in either order into the second and third answer boxes with only one dx or dy...
5. 0/12 points I Previous Answers My Use F- 14r to answer the questions below. (a) S, is the part of the surface -8-) above the plane z5 oriented upward Because the surface is a function of x and y, express F in terms of x and y only. Find dA Set up the iterated integral for flux dr de Evaluate the integral Flux through S (b) S2 is the horizontal disk of radius V3 centered at (0, 0, 5)...
Let F(x, y, z) = xi + yj + zk and S be the surface defined by z = 9 – 22 - y2 and 2 > 0. Evaluate SsFinds, where n is the upward unit normal vector.
(1 point) Let S be the part of the plane z 4 y which lies in the first octant, oriented upward. Evaluate the flux integral of the vector field F 2i + j + 3k across the surface S (with N being the unit upward vector normal to the plane). B.I 48 C. I 72 E. 1 24 (1 point) Let S be the part of the plane z 4 y which lies in the first octant, oriented upward. Evaluate...
using this formula 2. Evaluate the surface integral F. dS, where F(x, y, z) = xi+yj+zk is taken over the paraboloid z=1 – x2 - y2, z > 0. SA errom bove de SS (-P (- Puerto Q + R) dA dy
4/5 points | Previous Answers 4 Let F yi5j - xzk. S is the part of the surface y x2 + z for 0 s y s 4, oriented n the positive y direction Find dA -2xi + j - 2zk dz . Set up the iterated integral for flux. Simplify your integrand. 2 2 - 2 sin(t)cos())r |(-2Asin()+ +5+ X - 0 Submit Answer Save Progress 4/5 points | Previous Answers 4 Let F yi5j - xzk. S is...
Evaluate the surface integral of IjF.dS where F-xi+yj-zk and σ is the (a) 2, oriented by a downward portion of z-Vx2+y which lies between z1 and normal. Evaluate the surface integral of IjF.dS where F-xi+yj-zk and σ is the (a) 2, oriented by a downward portion of z-Vx2+y which lies between z1 and normal.
Evaluate the flux integral SF F . ds where F = (57, 22, 2x) and Sis the part of the plane 4x + 4y + z = 16 in the first octant oriented upward.
Problem #7: Find the flux of the vector field F = xi + 4xj + zk through the surface S given by that portion of the plane 4x + y + 5z = 10 in the first octant, oriented upward. Problem #7: Enter your answer symbolically, as in these examples
2. Evaluate the surface integral [[Fids. (a) F(x, y, z) - xi + yj + 2zk, S is the part of the paraboloid z - x2 + y2, 251 (b) F(x, y, z) = (z, x-z, y), S is the triangle with vertices (1,0,0), (0, 1,0), and (0,0,1), oriented downward (c) F-(y. -x,z), S is the upward helicoid parametrized by r(u, v) = (UCOS v, usin v,V), osus 2, OSVS (Hint: Tu x Ty = (sin v, -cos v, u).)...