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2. The following is the free body diagram of the arm showing the vertical and horizontal components of the force exerted by t
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) 6= 0.22 Fy 10-0.105t 0.01 Fy=0---(2) method: (a) Sulastitution Fs b.22 (0.22 ,) +0.01 FH-0 ID-0.10X F& 33.33 t 0.012 FH= 10A2- T.O Aplaying Krames ule 2.2 +9 AI 183.33 N O.012 Ans) Ar FH &33.33 N O.012 AF B F A 6 -O.22 F - O-10 TH -O.00 -0.10 0.22

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