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A 30-kg girl is bouncing on a trampoline. During a certain interval after she leaves the...

A 30-kg girl is bouncing on a trampoline. During a certain interval after she leaves the surface of the trampoline, her kinetic energy decreases to 210 J to 380 J. How high does she rise during this interval? Neglect air resistance.
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Answer #1

ΔK + ΔP = 0 ;

210 - 380 = - ΔP ;

ΔP = 170 ;

mgh = 170 ;

30 * 9.8 h = 170 ;

h = 0.578231 m <-------ans

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Answer #2
increase in potential energy = decrease in KE
Or, 30 *9.8 * h =170
so, h =.578 metre
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