According to Raoult's law for a solution of volatile liquids, the partial pressure of a solvent is directly proportional to the mole fraction of that solvent.
Let us assume two volatile liquids A & B
PA = XA P°A
PB= XB P°B
Given that
Number of moles of Toluene = 5.50 moles
Number of moles of Naphthalene = 0.32 moles
Mole fraction of Naphthalene = 0.32/0.32+5.50
Mole fraction of Toluene = 5.50/0.32+5.50
Pressure of pure Toluene = 41 torr
Partial pressure of toluene =( 0.32 /(0.32+5.5) ) * 41 torr
= 2.3 torr
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