Question

Please explain your reasoning.

4. You have a square parallel plate capacitor with capacitance C. The plates are separated by a distance d and each square plate has a side length of L. Ifyou double the separation distance to 2d and half the side length to 0.5L, what is the new capacitance? A. 8C В. С C) 0.125C D. 4C E. 0.25C If the electric potential in space is given by the function V (x, y) = [2x3 + x2 - 4y2] Volts, what is the Electric field at the point (x.y)- (1, 3)? 5. E = [+32-36f ] ) EI-8t+24/] c. [-21+ 4j1 d. E-25.3 ( e. E-I+1-31

Answer 1

© Cote d - EOLE 4 C. - Eode 3)C, - € (0.5L)? 720) 5) Cz = boli = $ 4. C. = G = 0.1256 option © V = (2x® + x°- 4y2), pero E --ov --Evitev s tebu ) =] = -((6+*+29) 7 + (-87)+(0)] È at (x, y) =(1,3) Ē = -(87-945) * = 4-87+243) Z E