Question

u Review | Constants Periodic Table First, consider a capacitor of capacitance C that has a charge Q and potential difference V. Learning Goal: To be able to calculate the energy of a charged capacitor and to understand the concept of energy associated with an electric field. The energy of a charged capacitor is given by U = QV/2, where Q is the charge of the capacitor and V is the potential difference across the capacitor. The energy of a charged capacitor can be described as the energy associated with the electric field created inside the capacitor. - Part A Find the energy U of the capacitor in terms of C and Q by using the definition of capacitance and the formula for the energy in a capacitor. Express your answer in terms of C and Q. In this problem, you will derive two more formulas for the energy of a charged capacitor, you will then use a parallel- plate capacitor as a vehicle for obtaining the formula for the energy density associated with an electric field. It will be useful to recall the definition of capacitance, C=Q/V, and the formula for the capacitance of a parallel-plate capacitor, IVO AQ * R 0 a ? U = C = € Ad, where A is the area of each of the plates and d is the plate separation. As usual, Eo is the permittivity of free space. Submit Request Answer Part B Complete previous part(s)

Answer 1

A) formula U = Qv capacitance ca e v=0 U = Qv u= ale U = Q 26