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5. Find a solution of a IVP consisting of the DE y-2 y=cie 3 6x+4, with...
(1 point) 6y 6xe-6x, 0 < x < 1 with initial condition y(0) = 2. Given the first order IVP y 0, х21 (1) Find the explicit solution on the interval 0 < x < 1 У(х) %3 (2) Find the lim y(x) = х—1 (3) Then find the explicit solution on the interval x 1 У(х) —
Reproduce the given computer-generated direction field. Then sketch an approximate solution curve that passes through each of the indicated points. dy-- dx (a) y(-2) = 1 (ь) у(3) - 0 (c) y(0) 2 (d) y(0) 0 Reproduce the given computer-generated direction field. Then sketch an approximate solution curve that passes through each of the indicated points. dy-- dx (a) y(-2) = 1 (ь) у(3) - 0 (c) y(0) 2 (d) y(0) 0
(1 point) Suppose y2 y2 3 3 2 2 y(t) = cie + cze [1] 1 y1 y1 [-1] 7(1) = [21] -3 -2 2 3 -3 -2 -1 1 2 3 -1 -2 -3 -3 (a) Find ci and C2 А B C1 = 1.3591 y2 y2 3 3 C2 = 0.1839 2 2 1 1 y1 y1 -2 -1 1 2 3 -3 -2 -1 1 2 3 (b) Sketch the phase plane trajectory that satisfies the given...
(1 point) Suppose y2 y2 3 3 2 2 y(t) = cie + cze [1] 1 y1 y1 [-1] 7(1) = [21] -3 -2 2 3 -3 -2 -1 1 2 3 -1 -2 -3 -3 (a) Find ci and C2 А B C1 = 1.3591 y2 y2 3 3 C2 = 0.1839 2 2 1 1 y1 y1 -2 -1 1 2 3 -3 -2 -1 1 2 3 (b) Sketch the phase plane trajectory that satisfies the given...
a) Solve the IVP: (x + y)2dx + (2xy + x2 - 1)dy = 0 ; y(1) = 1 b) Find a continuous solution satisfying the given De subject to initial condition. dy + 2x y = f(x), f(x) = fx, 05x<1 y(0) = 2 dx 10, 821 c) Solve the Bernoulli's equation xy' + y = x²y2
y = 1/(x2 + c) is a one-parameter family of solutions of the first-order DE y' + 2xy2 = 0. Find a solution of the first-order IVP consisting of this differential equation and the given initial condition. y(-3) = y = Find the domain of y considered as a function over the reals. (Enter your answer using interval notation.) Give the largest interval I over which the solution is defined for the given initial condition. (Enter your answer using interval...
The solution of the Initial-Value Problem (IVP) z? yll – 2y = 4(x - 2) y(1) = 4 y (1) = -1 is . 4 y == + x2 - 2x + 1 2 None of them 0 1 O y = +22 - 2x + 4 2 O y = 1 +73 - 2x + 4 22 O v= +222+3
solution for all 4 please In Problems 1-3, solve the given DE or IVP (Initial-Value Problem). [First, you need to determine what type of DE it is. 1. (2xy + cos y) dx + (x2 – x sin y – 2y) dy = 0. 1 dy 2. + cos2 - 2.cy y(y + sin x), y(0) = 1. + y2 dc 3. [2xy cos (2²y) – sin x) dx + x2 cos (x²y) dy = 0. (1+y! x" y® is...
Solve using Matlab Use the forward Euler method, Vi+,-Vi+(4+1-tinti ,Vi) for i= 0,1,2, , taking yo y(to) to be the initial condition, to approximate the solution at t-2 of the IVP y'=y-t2 + 1, 0-t-2, y(0) = 0.5. Use N = 2k, k = 1, 2, , 20 equispaced time steps (so to = 0 and tN-1 = 2). Make a convergence plot, computing the error by comparing with the exact solution, y: t1)2 -exp(t)/2, and plotting the error as...
dicated initial condition. In #4-5, find the particular solution for each differential equation given the indicated initial 4 de -cosx=0, 600)=1. s. 1-2x = 0, y(0)= In 2