Question

Review 1 Constants Periodic Table PartA A 0.800 kg block is attached to a spring with spring constant 16 N/m. While the block is sitting at rest, a student hits it with a hammer and almost instantaneously gives it a speed of 43 cm/s What is the amplitude of the subsequent oscillations? Express your answer in centimeters Submit Part B What is the block's speed at the point where z = 0.25/47 Express your answer in centimeters per second.

Answer 1

Solution,

A)

From law of conservation of energy,

0.5 mv^2 = 0.5 kA^2

A = sqrt(mv^2/k)

A = sqrt[0.8 x 0.43^2/16] = 0.096 m

Amplitude A = 9.62 cm

B)

Again using law of conservation of energy,

Velocity, V = sqrt[v^2 - (k/m) x^2]

V = sqrt[0.43^2 - (16/0.8) (0.25 x 0.0962)^2]

Velocity V = 41.63 cm/s

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