Question

3.2.33 Question Help Refer to the frequency distribution and find the standard deviation by using the formula Blood Platelet Count of Males (1000 cells/uL) Frequency 0-99 100-199 200-299 300-399 400-499 500-599 600-699 41 82 24 where x represents the class midpoint, f represents the class frequency, and n represents the total number of sample values. Compare this value with the standard deviation found using the original list of data values, 68.2 s-Π (1000 cells/uL) Round to one decimal place as needed.) Enter your answer in the answer box and then click Check Answer Clear All Check Answer remaining

Answer 1

The grouped data information provided, with the corresponding frequencies is shown in the table below Classes 0-99 100-199 200-299 300-399 400-499 500-599 Frequency (f) 82 24 For each of the grouped classes we need to compute the midpoint (M), by calculating the average between the lower and upper value of the class. Then, the following table si obtained Classes 0-99 100-199 200-299 300-399 400-499 500-599 600-699 49.5 149.5 249.5 349.5 449.5 549.5 649.5 M-f 148.5 6129.5 20459 8388 M2.f 7350.75 916360.25 5104520.5 2931606 41 82 24 649.5 421850.2 9381687.7 Sum = 151 35774.5 From the table, we compute the sample mean X as follows Mf (35774.5) 236.917 151 Also, the sample variable is calculated as follows: var(X)-1 9381687.75 35774.52 6040.618 151 -1 151 Therefore, the sample sandartd deviation s is directly computed by taking the square root from the sample variance Ss2-6040.618 77.721

S = 77.7

Please rate