Question

Practice Assessment Create new Due Sun 02/03/2019 1 Entry Tip: Enter your answers as decimals or fractions, rather than percents. In a family with 6 children what is the probability of having 4 boys and then 2 girls, in that order? (Exclude multiple births and assume all outcomes are equally likely). Preview In a family with 6 children, what is the probability of having 4 boys and 2 girls, in any order? (Exclude multiple births and assume all outcor are equally likely). Preview Points possible: 4 Unlimited attempts Message instructor about this question Submit

Answer 1

1) Given, both outcomes are equally likely.

Let B denote boy and G denote girl.

We need the order BBBBGG

Required probability = (0.5)⁶ =0.1563

2) Since ordering is not considered, this becomes a case of binomial probability

Binomial probability is given by,

$P(X=x)=\binom{n}{x}p^{x}(1-p)^{n-x}$

where ,

n is the number of trials

x is the number of successes

p is the probability of success

Given,

p=0.5(outcomes are equally likely)

x=4

n=6

$P(X=4)=\binom{6}{4}(0.5)^{4}(0.5)^{2}=0.2344$