Question

i only need help with the curcled problems please

0 12 S 4 MnO,- + 12 s- + + 4 MnO2 + 3 Ss + 1LOH H2O H2O 4 MnO2 Oxidation Half Reaction: Reduction Half Reaction: Oxidizing agent: Reducing agent 12. HS + NO:" + H N O2 + S8 + H20 Oxidation Half Reaction: Reduction Half Reaction: Oxidizing agent: Reducing agent Not H 702 + + N₂ + H₂O

Answer 1

روی میز در BifoH? ( 2) - SH (OH), Snom t Be X- - Oxlation X-6 = 2 (x2+4) Oxillising Year - :64}, reducing agent - Sacown- Onidation Hall nection - (+4 - Snowit 22- +3H*]*} Sncom} + 3H, change in oxidation State in 2 Recolereticu may reaction - "Pronz + 36 +340 – $*+ 340 342 Bi (OH 3 + 2H- Bi + 3,0 - change in Ouidation state is 3

Multiplying requation ③ by 3 and equation ② by 2 and then adding them 3 Sn(012" + 9 4,0 + 2 Belom2 + CH — 3 Sm(orto + 9 HB r 2 B1 + 6H,O, 3 Sn(4%. + 311,0 + 2 B.You? —- 3 Sncomylom +370 + 2016 Adding 3 oft on both the risibles we get, 3 Sncon)+ 34,0 + 2 Bicoh + 3017 ~ 3 Snow! +34*+2014+261 3H₂O 359(04) + 346 + 2 BI (on), +301 -> 3 Sncome?*3*20*230 3811063 + 2 60401] + 3011 - ? sncome + 2B L - reduction Reduction Half reaction - - M . 2 Onidation Mall reaction - bonidation + 3e+4H- Change in onidation state the + 2H2oJx16 - so +16e] *3 ge in onication state is 16 2 [8gr 1 (1) - 16 mnou +84 H* + 245² - 16 Mng +35₂ + 32 Hao Adding 64 off on both the sides, 16 Mnon +64 + + + 64 OFT + 24 5² - 18 Mnoz 13 Sg + 3240 * 64 of 16 Mnoy +64 H2O + 2452 - 16 MnO2 + 1 Sp +32H20 +64 of 16Mnou + 324₂0 +2452 - 16 MnQ + 3 Sp + 64 07. Onidining agent - Mnoir Reduring agent - st.