Question

Question 15 1 pts Given that AGºrxn = 3.79 kj for the following reaction at 289 K, calculate the equilibrium concentration of C if the equilibrium concentrations of A = 0.82 M and B = 0.56 M. Enter the result with 3 s.f. and scientific notation. 1A + 3B — 3C

Answer 1

T = 289 K

ΔGo = 3.79 KJ/mol

ΔGo = 3790 J/mol

use:

ΔGo = -R*T*ln Kc

3790 = - 8.314*289.0* ln(Kc)

ln Kc = -1.5774

Kc = 0.2065

Kc is defined as concentration of product by concentration of reactant with each concentration term raised to power that is equal to its stoichiometric coefficient in balanced equation

So,

Kc = [C]^3 / [A][B]^3

0.2065 = [C]^3 / (0.82 * 0.56^3)

0.2065 = [C]^3 / 0.144

[C]^3 = 0.02974

[C] = 0.310 M

Answer: 0.310 M