please help. it's my physics class.
here,
the uniform speed of player 1 , u1 = 18 m/s
t1 = 2 s
accelration of seccond player , a2 = 4.3 m/s^2
let the time taken to catch be t and distance travelled by seccond player be s
for first player
s = (u1 * t1 + u1 * t)
s = ( 18 * 2 + 18 * t) ....(1)
and
for seccond player
s = 0 + 0.5 * a2 * t^2
s = 0 + 0.5 * 4.3 * t^2 ....(2)
from (1) and (2)
s = 216.7 m
t = 10.04 m
a)
the time taken is 10.04 m
b)
the distance travelled is 216.7 m
please help. it's my physics class. 39. A hockey player is standing on his skates on...
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