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Nine owners of Honda Civics in Richmond want to know if they get different gas mileage with their cars than what the Honda Corporation reports. Honda of America states that all Honda Civics sold in America get an average of 33 MPG (miles per gallon). The nine Honda owners drive their cars and record the MPG listed below. Use a single-sample t-test to determine the outcome (alpha .05, two-tailed). Owner 1: 29 MPG Owner 2: 32 MPG Owner 3: 31 MPG Owner 4: 30 MPG Owner 5: 30 MPG Owner 6: 29 MPG Owner 7: 28 MPG Owner 8: 31 MPG Owner 9:30 MPG M- 30 In the box below, provide the following information Null Hypothesis in sentence form (1 point): Alternative Hypothesis in sentence form (1 point): Critical Value(s) (2 points): Calculations (4 points);: Note: the more detail you provide, the more partial credit that I can give you if you make a mistake. Outcome (determination of significance or not, and what this reflects in everyday language, 2 points)
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Answer #1

sd = 1.224745

The provided sample mean is X - 30 and the sample standard deviation is s the sample size is n -9 1.224744871, and The following null and alternative hypotheses need to be tested Но: -33 на: #33 This corresponds to a two-tailed test, for which a t-test for one mean, with unknown population standard deviation will be used (2) Rejection Region Based on the information provided, the significance level is a -0.05, and the critical value for a two- tailed test is tc- 2.306 The rejection region for this two-tailed test is R-It : t 2.306 (3)_Test Statistics The t-statistic is computed as follows 30- 33 1.224744871/v/J lo 7348 s/Vn Since it is observed that7.348te 2.306, it is then concluded that the null hypothesis is rejected Using the P-value approach: The p-value is p 0.0001, and since p 0.0001 < 0.05, it is concluded that the null hypothesis is rejected (5) Conclusion It is concluded that the null hypothesis Ho is rejected. Therefore, there is enough evidence to clainm that the population mean u is different than 33, at the 0.05 significance level The 95% confidence interval is 29.059 30.941

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