Question

IN C++!!

Program 2: BACK AWAY FROM THE TV! If you sat close enough to an old TV, you could see individual (R)ed, (G)reen and (B)lue (or RGB) “phosphors” that could represent just about any color you could imagine (using “additive color model”). When these three color components are at their maximum values, the resulting color is white from a distance (which is amazing – look at your screen with a magnifying glass!). When all are off, the color results in black. If red and green are fully on, you’d get a shade of yellow; red and blue on would result in purple, and so on. For computers, each color component is usually represented by one byte (8 bits), and there are 256 different values (0-255) for each. To find the “inverse” of a color (like triple-clicking your iFone® button), you subtract the RGB values from 255. The “luminance” (or brightness) of the color = (0.2126*R + 0.7152*G + 0.0722*B).

For this program, you need to design (pseudocode) and implement (source code) a Color class that has R, G and B attributes (which can be ints). The constructor should take three parameters representing the initial color of (R:254, G:2, B:100). You should include 6 methods to increase and decrease each component, not to exceed 255 or be less than 0. You should include a method (usually called “toString”) that returns a string representing the current values for each component as well as the luminance. Finally, you should include a method that calculates and prints the inverse color.

Next, create a “driver” (or main) that creates a default color, prints its values to the screen, and enables the user to increase/decrease values as well as print the inverse. It should behave like below.

Sample run:

R:254 G:2 B:100 L:62.6508

Do you want to:

1) Increase Red, 2) Decrease Red

3) Increase Green, 4) Decrease Green

5) Increase Blue, 6) Decrease Blue

7) Print the inverse

or 8) Quit

1

R:255 G:2 B:100 L:62.8634

Do you want to:

1) Increase Red, 2) Decrease Red

3) Increase Green, 4) Decrease Green

5) Increase Blue, 6) Decrease Blue

7) Print the inverse

or 8) Quit

1

R:255 G:2 B:100 L:62.8634

Do you want to:

1) Increase Red, 2) Decrease Red

3) Increase Green, 4) Decrease Green

5) Increase Blue, 6) Decrease Blue

7) Print the inverse

or 8) Quit

7

Inverse is R:0 G:253 B:155

R:255 G:2 B:100 L:62.8634

Do you want to:

1) Increase Red, 2) Decrease Red

3) Increase Green, 4) Decrease Green

5) Increase Blue, 6) Decrease Blue

7) Print the inverse

or 8) Quit

8

R:255 G:2 B:100 L:62.8634

Answer 1

#include
#include
#include
#include
using namespace std;

class MyColor{
private:
double luminance;
  
void setLuminance(){
luminance = 0.2126*R + 0.7152*G + 0.0722*B;
}
public:
static const int MAX = 255;
static const int MIN = 0;
int R,G,B;
  
MyColor(int r, int g, int b){
R = r;
G = g;
B = b;
setLuminance();
}
void increaseRed(){
if(R < MAX)
R++;
setLuminance();
}
void decreaseRed(){
if(R > MIN)
R--;
setLuminance();
}
  
void increaseGreen(){
if(G < MAX)
G++;
setLuminance();
}
void decreaseGreen(){
if(G > MIN)
G--;
setLuminance();
}
  
void increaseBlue(){
if(B < MAX)
B++;
setLuminance();
}
void decreaseBlue(){
if(B > MIN)
B--;
setLuminance();
}
void printInverse(){
cout << "R: "<< (255-R) <<" G: "<< (255-G) <<" B: "<< (255-B);
cout << " L:" << (0.2126*(255-R) + 0.7152*(255-G) + 0.0722*(255-B));
}
  
string toString() const{
return "R:" + to_string(R) +" G: " + to_string(G) + " B:" + to_string(B) + " L:" + to_string(luminance);
}
};

int main(){
MyColor col(155,254,2);
cout << col.toString();
int choice = 0;
  
while(choice != 8) {
//col.printColor();
cout << "\nDo you want to:"
<< "\n1) Increase Red, \n2) Decrease Red"
<< "\n3) Increase Green, \n4) Decrease Green"
<< "\n5) Increase Blue, \n6) Decrease Blue"
<< "\n7) Print the inverse"
<< " or \n8) Quit";
cout << "\nPlease enter your choice: ";
cin >> choice;
switch(choice){
  
case 1:
col.increaseRed();
break;
case 2:
col.decreaseRed();
break;
case 3:
col.increaseGreen();
break;
case 4:
col.decreaseGreen();
break;
case 5:
col.increaseBlue();
break;
case 6:
col.decreaseBlue();
break;
case 7:
col.printInverse();
break;
case 8:
cout<< "Thank You!";
break;
default:
cout << "Invalid Choice";
}
cout << endl<< col.toString()< }

return 0;
}

75 cout "\ndo vou want to." R:155 G: 254 B:2 1:214.758200 Do you want to: 1) Increase Red, 2) Decrease Red 3) Increase Green, 4) Decrease Green 5) Increase Blue, 6) Decrease Blue 7) Print the inverse or 8) Quit Please enter your choice: 1 R:156 G: 254 B:2 1:214.970800 Do you want to: 1) Increase Red, 2) Decrease Red 3) Increase Green, 4)Decrease Green 5) Increase Blue, 6) Decrease Blue