Find the value of the standard normal random variable z, called z0 such that:
(a) P(z≤z0)=0.7909P(z≤z0)=0.7909
z0=
(b) P(−z0≤z≤z0)=0.6892P(−z0≤z≤z0)=0.6892
z0=
(c) P(−z0≤z≤z0)=0.98P(−z0≤z≤z0)=0.98
z0=
(d) P(z≥z0)=0.1258P(z≥z0)=0.1258
z0=
(e) P(−z0≤z≤0)=0.1431P(−z0≤z≤0)=0.1431
z0=
(f) P(−1.22≤z≤z0)=0.4883P(−1.22≤z≤z0)=0.4883
z0=
Find the value of the standard normal random variablez, called z0 such that:...
Find the value of the standard normal random variable z, called z0 such that: (a) P(z≤z0)=0.7247 z0= (b) P(−z0≤z≤z0)=0.504 z0= (c) P(−z0≤z≤z0)=0.41 z0= (d) P(z≥z0)=0.0112 z0= (e) P(−z0≤z≤0)=0.1587 z0= (f) P(−1.21≤z≤z0)=0.6928 z0=
Find a value of a standard normal random variable Z (call it z0) such that (a) P(Z ?20) .30 (b) P(Z> z)16 (c) P(-20< Z<20).90
(1 point) Find the value of the standard normal random variable z, called Zo such that: (a) P(Z <zo) = 0.8319 20 (b) PC-Zo <z<zo) = 0.5508 20 = (c) P(-20 <2<zo) = 0.748 zo = (d) P(z > Zo) = 0.2823 20 = (e) P(-20 <z<0) = 0.0283 Zo = (1) P(-1.5 <2<zo) = 0.7108 zo Note: You can earn partial credit on this problem.
3)using excel and Given that z is a standard normal random variable, what is the value for z0 if: a. P(z > z0) = 0.12 b. P(z < z0) = 0.2 c. P(z > z0) = 0.25 d. P(z < z0) = 0.3
Question 11 4 pts Find an approximate value of the standard normal random variable z, called to such that P (2>20) = 0.70. O -0.52 O -0.98 -0.47 -0.81 < Previous Next
For standadrd normal random variable Z, (i) given p(Z < z0) = 0.1056, find z0-score, (ii) Given p(-z0 < Z < -1) = 0.0531, find z0-score, (iii) Given p(Z < z0) = 0.05, find z0-score.
Find an approximate value of the standard normal random variable z, called zor such that P(Z >20) = 0.70. 0 -0.47 -0.52 0 -0.99 -0.81
Find a value of the standard normal random variable z, call it zo such that the following probabilities are satisfied. a. P(z Szo)=0.0473 b. P(- zo szszo)=0.99 c. P(-20 sz szo)=0.95 d. P(-20 52520) = 0 8358 e. P(-20 Sz50)= 0.2612 f. P(-2<z<zo)=0.9503 g. P(z>20)=0.5 h. PZSzo) = 0.0027
Find a value of the standard normal random variable z, call it 20, such that the following probabilities are satisfied. a. P(zszo)=0.0502 b. P(-2o Szszo)=0.99 c. P(-zo szszo)=0.90 d. P(- zo szszo) = 0.8062 e. P(-Zo Szs 0) = 0.2593 f. P(-3<z<zo)=0.9654 g. Plz>20) = 0.5 h. Plz szo) = 0.0088
(1 point) Let Z be a standard normal random variable. In each of the following, find the number zo which makes the indicated probability statement correct. (a) P(Z zo)-0.9343 Z0 (b) P(-Zo S Z zo) -0,781 Zo - (c) P(-zo K Z K zo) 0.64 Zo (d) P(Z 2 zo) 0.2914 (e) P(-Zo KZ30)-0.2319 (0 P(-1.51SZS zo) 0.5152 Zo