Question

Engineers want to design seats in commercial aircraft so that they are wide enough to fit 95% of all males (Accommodating 100% of males would require very wide seats that would be much too expensive.) Men have hip breadths that are normally distributed with a mean of 14.6 in, and a standard deviation of 0.8 in. Find Pgs. That is, find the hip breadth for men that separates the smallest 95% from the largest 5%. 

The hip breadth for men that separates the smallest 95% from the largest 5% is P95 = _______ in (Round to one decimal place as needed.) 

Answer 1

From the given information,

Mean= 14.6

Sd= 0.8

Hence,

By using percentile calculator,

The required correct answer is,

P95= 15.9 in.

Thank you.

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