Question

About 7% of the population has a particular genetic mutation. 100 people are randomly selected.

Find the standard deviation for the number of people with the genetic mutation in such groups of 100. Round your answer to three decimal places

Answer 1

Let \(X\) be a random variable denoting the number of people having genetic mutation out of 100 people and it follows Binomial Distribution with parameters \(n=100\) and \(p=0.07\)

The standard deviation of \(X\) is:

$$ \begin{aligned} S d(x) &=\sqrt{n p(1-p)} \\ &=\sqrt{100(0.07)(1-0.07)} \\ &=2.551 \end{aligned} $$