Question

Suppose a deck of 52 cards is shuffled and the top two cards are dealt. Assuming each of these pairs has the same chance, calculate: b) the chance that the first card is an ace; c) the chance that the...

Suppose a deck of 52 cards is shuffled and the top two cards are dealt.

Assuming each of these pairs has the same chance, calculate:

b) the chance that the first card is an ace;

c) the chance that the second card is an ace (explain your answer by a symmetry argument as well as by counting);

please answer question C based on B in detail. Better to write down the answer step by step, thank you

0 0
Add a comment Improve this question Transcribed image text
Answer #1

b) chance that the first card is an ace =(4/52 )=1/13 (As there are 4 ace in 52 cards)

c) here from symmetry argument ; as we do not have prior information therefore each card has same probability of being ace. Hence proability that 2nd card is ace =4/52 =1/13

from counting :

P(2nd card is ace)=P(first card not ace and 2nd card is ace)+P(first card ace and 2nd card is ace)

=(48/52)*(4/51)+(4/52)*(3/51) =(4/52)*(48/51+3/51)=(1/13)*1 =1/13

Add a comment
Know the answer?
Add Answer to:
Suppose a deck of 52 cards is shuffled and the top two cards are dealt. Assuming each of these pairs has the same chance, calculate: b) the chance that the first card is an ace; c) the chance that the...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT