Question

Calculate the mass of tetraborane B4H10 that contains a trillion ×1.0001012 boron atoms. Be sure your answer has a unit symbol if necessary, and round it to 4 significant digits.

Answer 1

All molar man of B4 H10 ² 53,32 g/mol By Hio = 4B + LOH I mule of boron contain 6.023 X 1023 borop atoms number I mole of Byto have 4 moles of boron & 4 mole of boron are present in Imole of B4 H10 4X 6.023 X 1023 boron atoms are present in Imole of By Ho 486.0 23 X 10 23 boron atoms are present in 53.32 g of By Hic - 100x10 12 boron atoms are present in mass of By HiO = 53.329 X 100 X 1012 4 X 6.02 3 8 10 23 trillion = 21 213X 10 9 By HIO Hence, the main of By Hio that contains a born atoms is 2,213 × 10-19 Please Rate