For the chemical reaction 2KI+Pb(NO3)2⟶PbI2+2KNO3 how many moles of lead(II) iodide (PbI2) are produced from 8.0...

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For the chemical reaction 2KI+Pb(NO3)2⟶PbI2+2KNO3 how many moles of lead(II) iodide (PbI2) are produced from 8.0...

For the chemical reaction
2KI+Pb(NO3)2⟶PbI2+2KNO3
how many moles of lead(II) iodide (PbI2) are produced from
8.0
mol of potassium iodide (KI)?

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Answer 1

Answer #1

QKI + Pb(NO3% Pb Iz + 2 KNO3 By son, 2 mol ki produce=1 mole Pb I2 & No 1 k pro е ее - x < ) ms) Pь Е, = [ч мо)) Pь I, polyce

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Answer 2

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