For the chemical reaction 2KI+Pb(NO3)2⟶PbI2+2KNO3 how many moles of lead(II) iodide (PbI2) are produced from 8.0...

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For the chemical reaction 2KI+Pb(NO3)2⟶PbI2+2KNO3 how many moles of lead(II) iodide (PbI2) are produced from 8.0...

For the chemical reaction
2KI+Pb(NO3)2⟶PbI2+2KNO3
how many moles of lead(II) iodide (PbI2) are produced from
8.0
mol of potassium iodide (KI)?

science chemistry

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Answer 1

Answer #1

The balanced chemical equation is:

2KI+Pb(NO3)2⟶PbI2+2KNO3

From above reaction,

Mol of PbI2 formed = (1/2)*moles of KI reacted

= (1/2)*8.0 mol

= 4.0 mol

Answer: 4.0 mol

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Answer 2

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