Balance Redox Equations (Acidic Solutions) show steps please.
1. HgS (s) + NO3^- (aq) + Cl^- (aq) = HgCl4^2- (aq) + NO (g) + S (s)
2. Fe^2+ (aq) + MnO4^- (aq) = Fe^3+ (aq) + Mn^2+ (aq)
3. BiO3^- (aq) + Mn^2+ (aq) = MnO4^- (aq) + Bi^3 (aq)
4. NiO2 (s) + Ag (s) = Ni^2+ (aq) + Ag^+ (aq)
5. IO3^- (aq) + I^- (aq) =I2 (s)
6. Zn (s) + H2SO4 (aq) = Zn^2+ (aq) + H2S (g)
Please post the last 2 separately.
Comment if any problem
Balance Redox Equations (Acidic Solutions) show steps please. 1. HgS (s) + NO3^- (aq) + Cl^-...
Balancing redox equations (acidic Solutions) 1. IO3^- (aq) + I^- (aq) =I2 (s) 2. Zn (s) + H2SO4 (aq) = Zn^2+ (aq) + H2S (g)
Balance Redox Equations (Basic Solution) with steps. 1. Mn^2+ (aq) + Br2(l) = MnO2 (s) + Br^- (aq) 2. NO2^- (aq) + MnO4^- (aq) = NO3^- (aq) + MnO2 (s) 3. N2H4 (g) + ClO3^- (aq) = NO(g) + Cl^- (aq)
use the example to answer 8,9,10&11 Here's an example: Balance the following redox reaction, which occurs in acidic solution: Fe (aq)+ MnO4'(aq) -Fe (aq) + Mn (aq) Solution: +2 +7 +3 Step 1) +2 Fe2 (aq)+ MnOa (aq) Fe(aq) + Mn2 (aq) Fe (aq) MnO4 (aq) Mn2 (aq) 1 Fe on each side; 1 Mn on each side; no adjustment necessary Fe2 (aq) Fe 3'(aq) + e 5 e + MnO4(aq) Fe (aq) Fe (aq) + e (2+ on each...
1. Balance the following reaction in acidic solution. I-(aq) + MnO4-(aq) Mn2+(aq) + I2(s) 2. Write a balanced net ionic equation for the following reaction in basic solution using both methods for balancing a redox reaction: Zn(s) + NO3-(aq) à NH3 (aq) + Zn(OH)42- (aq) 3. Write a balanced net ionic equation for the following reaction in basic solution using both methods for balancing a redox reaction: MnO4-(aq) + C2H5OH(aq) à Mn2+(aq) + HC2H3O2 (aq)
Balance each redox reaction occurring in acidic aqueous solution. a. PbO2(s) + (aq) Pb2+(aq) + 12(s) b. SO32-(aq) + MnO4 (aq) — 3042-(aq) + Mn²+(aq) c. S2032-(aq) + Cl2(g) 8042-(aq) + Cl²(aq)
Balance following redox reactions in acidic conditions using the half-reaction method a. Fe + Ag+ → Fe2+ + Ag b. I- + SO42- → H2S + I2 c. Cu + NO3- → Cu2+ + NO2 d. PbO₂ + CI- → Pb2+ + Cl₂
help me balance the redox equations (acidic solutions) 1) BrO3- + Br- —> Br2 2) IO3- + I- —> I2 3) C2H4 + MnO-4 —> Mn2+ + CO2
Balance the following redox equations by the half-reaction method: (a) Mn2+ + H2O2 → MnO2 + H2O (in basic solution) (b) Bi(OH)3 + SnO22− → SnO32− + Bi (in basic solution) (c) Cr2O72− + C2O42− → Cr3+ + CO2 (in acidic solution) (d) ClO3− + Cl− → Cl2 + ClO2 (in acidic solution) (e) Mn2+ + BiO3− → Bi3+ + MnO4− (in acidic solution)
19. a. Balance the following redox reaction if it occurs in acidic solution. How many electrons are transferred, and what are the half reaction potentials? Fe 2+(aq) + MnO4 ?(aq) ? Fe 3+(aq) + Mn 2+(aq) b. What element is being oxidized, and what is the oxidizing agent in the given redox reaction? Mg2+(aq) + NH4 +(aq) ? Mg(s) + NO3 ?(aq)
Balance each of the following redox reactions occurring in acidic solution. 1. I−(aq)+NO−2(aq)→I2(s)+NO(g) 2. IO3−(aq)+H2SO3(aq)→I2(aq)+SO42−(aq) 3. NO−3(aq)+Sn2+(aq)→Sn4+(aq)+NO(g)