Predict the ground-state electron configuration of each ion. Use the abbreviated noble gas notation.

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Answer 1

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Answer #1

Ru Atomic number = 44 ,
so electron configuration = [Kr] 4d7 5s1

2 valance electron from above atom is removed , we get Ru2+

electron configuration of
Ru2+ =[ Kr] 4d6
**************************
W Atomic number = 74 ,
so electron configuration = [Xe] 4f14 5d4 6s2

3 valance electron from above atom is removed , we get W3+

W3+
electron configuration : [Xe] 4f14 5d3

Answer 2

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