Question

Be sure to answer all parts. Complete the following precipitation reaction with balanced molecular, total ionic, and net ionic equations. Remember to include the proper physical states and charges of ions. When writing ions, if a charge number is not "1", place the charge number before the charge sign. If a charge number is "1", do not include the charge number in the formula. Na2S(aq) + ZnSO4(aq) → Molecular: Total ionic: ReactantsProducts→Net ionic:

Answer 1

1)

we have below given Molecular equation

Na₂S (aq) + ZnSO₄ (aq) --> ZnS (s) + Na₂SO₄ (aq)

2)

Total ionic equation is

Spectator ions should not be removed here. Spectator ions are part of total ionic equation

2 Na⁺ (aq) + S^2- (aq) + Zn²⁺ (aq) + SO₄^2- (aq) -> ZnS (s) + 2 Na⁺ (aq) + SO₄^2- (aq)

3)

Spectator ions should be removed now. Spectator ions are not part of total ionic equation

After removing Spectator ions, net ionic equation is:

S^2- (aq) + Zn²⁺ (aq) -> ZnS (s)