Question

USUH UI) value 4.00 points 2 attempts left Check my work Be sure to answer all parts. Complete the following precipitation reaction with balanced molecular, total lonic, and net lonie equations. Remember to include the proper physical states and charges of ions. When writing fons, if a charge number is not "1". place the charge number before the charge sign. If a charge number is "1", do not include the charge number in the formula Na (aq) + ZnSO4(aq) - Molecular: Total ionic: Reactants Products Net ionic:

Answer 1

The given reaction is Na S (aq) + ZnSO4 (aq) → Na2SO4 (aq) + ZnS (s) This Balanced molecular equation Molecular equation is Na2S (aq) + ZnSO4 (aq) → Na2SO4 (aq) + ZnS (s) Total ionic equation, Write the soluble ionic compounds as dissociated ions, and non-soluble compounds expressed same as it is. 2Nat (aq) + (aq) + Zn2+ (aq) + SOA? (aq) + 2Na+ (aq) + SO42 (aq) + ZnS (8) Total ionic equation is 2Na+ (aq) +s? aq) + Zn2+ (aq) +SO2 (aq) → 2Na+ (aq) + SO4 (aq) + ZnS (8) Products are Na2SO4 (aq) + ZnS (s) Net ionic equation Representation of product ZnS (s), didn't change in the reaction, due to it is not soluble. In the complete ionic equation, we see that Nat' and I is present as reactand and as a product. Ionic species are not changed in the reaction are called spectator ions. We can cancel out spectator ions from our complete ionic equation since they appear on both sides of the equation. In this reaction spectator ions are the Nat and I. Therefore net ionic equation is 2N** **e) + S2 (aq) + Zn2+ (aq) + se. tag) 2Na+1) + Se e ) + ZnS (8) S2 (aq) + Zn²+ (aq) → ZnS (s) (this is the net ionic equation) Net ionic equation is $ (aq) + Zn + (aq) → ZnS (s)