Question

Hydrazine, N2H4 , reacts with oxygen to form nitrogen gas and water. N2H4(aq)+O2(g)⟶N2(g)+2H2O(l)

If 4.05 g of N2H4 reacts with excess oxygen and produces 0.750 L of N2 , at 295 K and 1.00 atm, what is the percent yield of the reaction?

Answer 1

N2H4 Ca9) 02cs)>N2) + 22u 4.09 gram Moleculan eint of Niu 32 gmd. Mole of Nau Geact = 405 oan 32 1mol =O 27 mle of N2Hy 010 Jte6t N2 V P6ocluce at 298K | ctm fsessune . bo no o v given b moles PYnRT RT lat mx o.asoL h- 0 0321 Latmkms"x29sk n= 0.03097 mden of N2oduce S-6om eaGioh We Canjce thed f5t mae oi N2N we gct nue of N 2 (). if 0.12 mae of N 2\d4 dcact but We get oh o309 we gel o7 molen of N2, mle o N2. ferented 0 3097 xlov O 127