Question

Given the two reactions H2S(aq)⇌HS−(aq)+H+(aq),   K1 = 9.62×10−8, and HS−(aq)⇌S2−(aq)+H+(aq),   K2 = 1.42×10−19, what is the equilibrium constant...

Given the two reactions

  1. H2S(aq)⇌HS−(aq)+H+(aq),   K1 = 9.62×10−8, and
  2. HS−(aq)⇌S2−(aq)+H+(aq),   K2 = 1.42×10−19,

what is the equilibrium constant Kfinal for the following reaction?

S2−(aq)+2H+(aq)⇌H2S(aq)

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Answer #1

H2S (aq) = HS-(aq) + H+(aq) ki - (HS -] [H+1 = 9.62 X10-8 (H2S) HS- (aq) = selaq) + H+ (aq) K2 = [s?] [H+? 1:42 X10-19 1.42

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Given the two reactions H2S(aq)⇌HS−(aq)+H+(aq),   K1 = 9.62×10−8, and HS−(aq)⇌S2−(aq)+H+(aq),   K2 = 1.42×10−19, what is the equilibrium constant...
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